(2y^2+3)(y-1)=0

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Solution for (2y^2+3)(y-1)=0 equation:


Simplifying
(2y2 + 3)(y + -1) = 0

Reorder the terms:
(3 + 2y2)(y + -1) = 0

Reorder the terms:
(3 + 2y2)(-1 + y) = 0

Multiply (3 + 2y2) * (-1 + y)
(3(-1 + y) + 2y2 * (-1 + y)) = 0
((-1 * 3 + y * 3) + 2y2 * (-1 + y)) = 0
((-3 + 3y) + 2y2 * (-1 + y)) = 0
(-3 + 3y + (-1 * 2y2 + y * 2y2)) = 0
(-3 + 3y + (-2y2 + 2y3)) = 0
(-3 + 3y + -2y2 + 2y3) = 0

Solving
-3 + 3y + -2y2 + 2y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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